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x^2=148
We move all terms to the left:
x^2-(148)=0
a = 1; b = 0; c = -148;
Δ = b2-4ac
Δ = 02-4·1·(-148)
Δ = 592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{592}=\sqrt{16*37}=\sqrt{16}*\sqrt{37}=4\sqrt{37}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{37}}{2*1}=\frac{0-4\sqrt{37}}{2} =-\frac{4\sqrt{37}}{2} =-2\sqrt{37} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{37}}{2*1}=\frac{0+4\sqrt{37}}{2} =\frac{4\sqrt{37}}{2} =2\sqrt{37} $
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